Relativistic Kinetic Energy Calculator
Enter rest mass and velocity (m/s or % of c) to compute the Lorentz factor, relativistic kinetic energy in joules and electron-volts, and classical KE for comparison.
Inputs
kg
c = 299,792,458 m/s
Quick examples
Results
Enter values above and click Calculate to see results.
Relativistic Kinetic Energy
0
J
Lorentz factor (γ)
Velocity entered
v/c ratio
Rest energy (mc²)
Total energy (γmc²)
Relativistic KE (γ−1)mc²
Classical KE (½mv²)
Relativistic correction
KE = (γ−1)mc² | γ = 1/√(1−v²/c²) | c = 299,792,458 m/s
Lorentz Factor Reference
| v/c (%) | γ | Correction vs. classical |
|---|---|---|
| 10% | 1.005 | +0.5% |
| 50% | 1.155 | +15% |
| 87% | 2.000 | +133% |
| 99% | 7.089 | +1,324% |
| 99.9% | 22.37 | +4,374% |
| 99.99% | 70.71 | +14,042% |
Correction = (KE_relativistic − KE_classical) / KE_classical × 100%
Copied!
Summary
Enter rest mass and velocity (m/s or % of c) to compute the Lorentz factor, relativistic kinetic energy in joules and electron-volts, and classical KE for comparison.
How it works
- Enter the rest mass of the object in kilograms.
- Enter the velocity either in metres per second (m/s) or as a percentage of the speed of light (% c).
- The calculator computes the Lorentz factor γ = 1/√(1−v²/c²).
- Rest energy mc², total energy γmc², and relativistic kinetic energy (γ−1)mc² are displayed in joules and electron-volts.
- Classical kinetic energy ½mv² appears alongside so you can compare the two.
- An error is shown if the entered velocity equals or exceeds c (299,792,458 m/s), since that is physically impossible for a massive object.
Use cases
- Physics students checking special-relativity homework involving particle energetics.
- Particle physicists converting beam kinetic energy between joules and electron-volts.
- Aerospace researchers estimating energy budgets for hypothetical near-lightspeed vehicles.
- Teachers demonstrating where classical mechanics breaks down relative to relativistic mechanics.
- Science communicators illustrating how much energy would be needed to accelerate a 1 kg mass to 99% of c.
Frequently Asked Questions
Last updated: 2026-07-01 ·
Reviewed by Nham Vu