Hydrogen Oxidation States

Quick reference for the three oxidation states of hydrogen (+1, −1, and 0) with real compound examples and the bonding rules that determine each state.

+1
Oxidation State +1
Most Common

Bonded to a more electronegative nonmetal

Hydrogen donates electron density to the more electronegative partner (O, N, Cl, F, S). It behaves as an electrophile or proton donor (Brønsted acid).

Examples
H₂O, HCl, NH₃, CH₄, H₂SO₄
−1
Oxidation State −1
Hydride

Bonded to a less electronegative metal

Hydrogen gains electron density from an electropositive metal and acts as the hydride ion (H⁻). These compounds are strong reducing agents.

Examples
NaH, CaH₂, LiH, LiAlH₄, MgH₂
0
Oxidation State 0
Elemental

Pure element or symmetric H–H bond

In diatomic H₂ both atoms are identical; electrons are shared equally so neither carries net charge. This is the reference state for standard enthalpies.

Examples
H₂ (gas), H• (atomic), H₂ plasma

Rules for Assigning Hydrogen's Oxidation State

1
Elemental hydrogen is always 0

The oxidation state of any pure element is defined as zero. For hydrogen this means H₂ gas, atomic H•, and any symmetrical H–H fragment.

Example: H₂, H•
2
Hydrogen bonded to nonmetals is +1

When hydrogen bonds to a more electronegative nonmetal (F, O, N, Cl, Br, I, S, C), it carries an oxidation state of +1. This covers water, all common acids, and nearly all organic C–H bonds.

Example: HF, H₂O, HCl, HNO₃, H₂SO₄, CH₄, NH₃
3
Hydrogen bonded to active metals is −1

When hydrogen bonds to Group 1 (alkali metals) or Group 2 (alkaline earth metals), or certain other electropositive metals, it is more electronegative and takes oxidation state −1 as the hydride ion H⁻.

Example: NaH, KH, LiH, CaH₂, BaH₂, MgH₂
4
Complex hydrides follow the metal rule

In complex reducing agents such as LiAlH₄ (lithium aluminum hydride) or NaBH₄ (sodium borohydride), hydrogen is still −1 because it is bonded to electropositive metal centers (Al or B acting as electron-deficient Lewis acids).

Example: LiAlH₄, NaBH₄, CaH₂ in THF
5
Overall charge neutrality is the check

After applying the rules above, verify that the sum of all oxidation states equals the overall charge of the species (0 for neutral molecules, −1 for anions like H⁻, etc.).

Example: H₂O: 2(+1) + (−2) = 0 ✓

Compound Examples by Oxidation State

Compound Formula H Oxidation State Class Notes
Water H₂O +1 Oxide +1 verified: O is −2, 2×(+1)+(−2)=0
Hydrochloric acid HCl +1 Halide acid Cl is −1; H is +1
Sulfuric acid H₂SO₄ +1 Oxyacid S is +6, O is −2; H is +1
Nitric acid HNO₃ +1 Oxyacid N is +5, O is −2; H is +1
Ammonia NH₃ +1 Molecular N is −3; 3×(+1)+(−3)=0
Methane CH₄ +1 Organic C is −4; 4×(+1)+(−4)=0
Hydrogen peroxide H₂O₂ +1 Peroxide O is −1; H remains +1
Phosphoric acid H₃PO₄ +1 Oxyacid P is +5, O is −2; H is +1
Sodium hydride NaH −1 Ionic hydride Na is +1; H is −1 (H⁻)
Calcium hydride CaH₂ −1 Ionic hydride Ca is +2; 2×(−1)+(+2)=0
Lithium hydride LiH −1 Ionic hydride Li is +1; H is −1
Lithium aluminum hydride LiAlH₄ −1 Complex hydride Al is +3; all 4 H are −1
Sodium borohydride NaBH₄ −1 Complex hydride B is +3; all 4 H are −1
Magnesium hydride MgH₂ −1 Ionic hydride Mg is +2; H is −1
Hydrogen gas H₂ 0 Elemental Symmetric bond; no net charge
Atomic hydrogen H• 0 Elemental Free radical; pure element state

Quick Oxidation State Lookup

Type a compound name or formula to find hydrogen's oxidation state in our reference list.

Start typing to filter compounds.

Decision Guide: Which State Applies?

Is hydrogen alone or in H₂?

If the compound is pure H₂ gas or atomic hydrogen H•, the oxidation state is 0 by definition. No further analysis needed.

Is hydrogen bonded to a metal?

If bonded to an alkali metal (Li, Na, K, Rb, Cs), alkaline earth metal (Mg, Ca, Ba), or another electropositive metal, hydrogen is −1 (hydride ion).

Is hydrogen bonded to a nonmetal?

If bonded to O, N, C, S, F, Cl, Br, or another nonmetal more electronegative than hydrogen, the oxidation state is +1. This is the default for the vast majority of compounds.

Hydrogen as a Reducing Agent

When H₂ (oxidation state 0) reacts and becomes H⁺ (+1), hydrogen is oxidized — it loses electron density. H₂ therefore acts as a reducing agent in these reactions.

H₂ → 2H⁺ + 2e⁻
(oxidation: 0 → +1)

Examples: combustion of H₂, fuel cell reactions, reduction of metal oxides.

Hydrogen as an Oxidizing Agent

When H₂ (oxidation state 0) reacts and becomes H⁻ (−1), hydrogen is reduced — it gains electron density. H₂ therefore acts as an oxidizing agent in these reactions.

H₂ + 2e⁻ → 2H⁻
(reduction: 0 → −1)

Examples: synthesis of NaH, CaH₂, LiH from metals and H₂ gas.

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Summary

Quick reference for the three oxidation states of hydrogen (+1, −1, and 0) with real compound examples and the bonding rules that determine each state.

How it works

  1. Review the three possible oxidation states: +1, −1, and 0.
  2. Check the bonding rule: hydrogen is +1 when bonded to a more electronegative nonmetal.
  3. Check the hydride rule: hydrogen is −1 when bonded to a less electronegative metal (Groups 1 and 2).
  4. Check the elemental rule: hydrogen is 0 in H₂ or in any symmetrical H–H bond.
  5. Browse the compound examples table to identify which state applies to a given molecule.
  6. Use the exceptions panel to handle edge cases like NaH, LiAlH₄, and interstitial hydrides.

Use cases

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Last updated: 2026-05-28 · Reviewed by Nham Vu